声明抽象基类Shape，由它派生出5个派生类；Circle(圆形)、Square（正方形）、Rectangle（矩形）、Trapezoid（梯形）、Triangle（三角形），分别计算几种图形的面积，并求它们的和并显示出来。请按照要求选择如下一种方式编程实现。 注意圆周率取3.14.
实现方式：
1.使用继承和派生完成上述功能。
2.使用动态多态完成上述功能，提示：基类指针+派生类对象。
3. 使用派生类构造函数知识完成上述功能。
4. 作业竞赛要求的其他方式
12.6
3.5
4.5 8.4
2.0 4.5 3.2
4.5 8.4
Circle:498.51
Square:12.25
Rectangle:37.80
Trapezoid:10.40
Triangle:18.90
total of all areas=577.86#include<iostream>
#include<iomanip>
using namespace std;
class Shape
{
public:
virtual double area() const=0;
};
class Circle:public Shape
//pdsu-c1
//pdsu-c1
class Square:public Shape
//pdsu-c2
//pdsu-c2
class Rectangle:public Shape
//pdsu-c3
//pdsu-c3
class Trapezoid:public Shape
//pdsu-c4
//pdsu-c4
class Triangle:public Shape
//pdsu-c5
//pdsu-c5
int main()
{
double a,b,c;
cin>>a;
Circle circle(a);
cin>>a;
Square square(a);
cin>>a>>b;
Rectangle rectangle(a,b);
cin>>a>>b>>c;
Trapezoid trapezoid(a,b,c);
cin>>a>>b;
Triangle triangle(a,b);
Shape *pt[5]=
{
&circle,&square,&rectangle,&trapezoid,&triangle
};
double areas=0.0;
for(int i=0; i<5; i++)
{
//pdsu-c6
//pdsu-c6
}
cout<<setiosflags(ios::fixed)<<setprecision(2);
cout<<"Circle:"<<pt[0]->area()<<endl;
cout<<"Square:"<<pt[1]->area()<<endl;
cout<<"Rectangle:"<<pt[2]->area()<<endl;
cout<<"Trapezoid:"<<pt[3]->area()<<endl;
cout<<"Triangle:"<<pt[4]->area()<<endl;
cout<<"total of all areas="<<areas<<endl;
return 0;
}
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